With an adult read and solve the mathematics problem below.
Posts will be published on our blog next Tuesday when homework is due. Year 6
teachers look forward to seeing your solutions!
Eight men and two boys want to cross a river
using a small canoe. The canoe can carry two boys or one man at any time.
How many times must the canoe cross the river
to get everyone to the other side?
Mum and I worked together to find out the answer. After a few attempts we are confident that the answer is 33 trips.
ReplyDeleteI calculated total trips to be 33. One cycle is 2 boys across one boy back, one man across the other boy back. There are eight men so there are eight cycles. The last trip is two boys across. (4x8)+1=33
ReplyDelete33 trips altogether
ReplyDeleteI solved this problem with my mum and my dad.
ReplyDeleteThe only way we could work it out was to use objects such as two oranges for the boys and 8 cherry tomatoes for the men. I started with; 2 boys crossed the river in the canoe, 1 boy got out and the other went back across the river to the men. Then the boy got out and one man got into the canoe and crossed the river. The man got out and the boy got in and went back across to pick up the other boy.They both went back across and one boy got out. Then the other boy in the canoe went back and got out and the second man got in and crossed the river.
This repeated 33 times until all of the boys and the men were on the other side of the river.
I solved the with Mum.
ReplyDeleteThe solution to the problem was,
2 boys go over, 1 boy returns, 1 man goes over, 1 boy returns, 2 boys go over, 1 boy returns, 1 man goes over, 1 boy returns, 2 boys go over, 1 boy returns, 1 man goes over, 1 boy returns, 2 boys go over, 1 boy returns, 1 man goes over, 1 boy returns, 2 boys go over 1 boy returns, 1 man goes over, 1 boy returns, 2 boys go over, 1 boy returns, 1 man goes over, 1 boy returns, 2 boys go over, 1 boy returns, 1 man goes over, 1 boy returns, 2 boys go over, 1 boy returns, 1 man goes over, 1 boy returns, 2 boys go over if you needed someone to be in the boat to go back.
Me and my dad discussed this and worked it out. First we did twos boys across and one boy back. Then one man went across and the other boy went back. Then the pattern repeated for each adult to get across so 8x4 trips plus one trip of getting the boys back equals 33.
ReplyDeleteI solved the problem with my mum and we got 33. We worked it out by sending 2 boys across. Next you send one back and one adult across. On boy comes back to get the canoe across and the solution is repeated. At the end you times 8 by 4 to get the adults across. Next you add one and that gives you the answer.
ReplyDeleteI worked out the problem with my Lola
ReplyDeleteMy Lola and I drew up charts of how the boys and men crossed the river. The continuing pattern was two boys go over, one comes back, one man goes over and one boy comes back. We repeated this pattern multiple times and our result was 33. So in conclusion it took the boys and men 33 times to cross the river to get everyone across.
Me and my dad discussed this and worked it out. First we did twos boys across and one boy back. Then one man went across and the other boy went back. Then the pattern repeated for each adult to get across so 8x4 trips plus one trip of getting the boys back equals 33.
ReplyDeleteI solved the problem with my mum.
ReplyDeleteThe solution to the problem was for the 2 boy's to go across first and one boy gets out and the other brings it back the boy gets out one man gets in and goes across gets out and the boy gets in and brings it back over. Do the same for the next 7 men then when the last man gets to the other side the kid on that side gets in and goes to the other side and both boy's get in and go to the other side were the 8 men are.
I ended up with 33 trips on the Canoe
ReplyDeleteIt is 33 trips
ReplyDelete